4c^2+19c+21=0

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Solution for 4c^2+19c+21=0 equation:


Simplifying
4c2 + 19c + 21 = 0

Reorder the terms:
21 + 19c + 4c2 = 0

Solving
21 + 19c + 4c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(3 + c)(7 + 4c) = 0

Subproblem 1

Set the factor '(3 + c)' equal to zero and attempt to solve: Simplifying 3 + c = 0 Solving 3 + c = 0 Move all terms containing c to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + c = 0 + -3 Combine like terms: 3 + -3 = 0 0 + c = 0 + -3 c = 0 + -3 Combine like terms: 0 + -3 = -3 c = -3 Simplifying c = -3

Subproblem 2

Set the factor '(7 + 4c)' equal to zero and attempt to solve: Simplifying 7 + 4c = 0 Solving 7 + 4c = 0 Move all terms containing c to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + 4c = 0 + -7 Combine like terms: 7 + -7 = 0 0 + 4c = 0 + -7 4c = 0 + -7 Combine like terms: 0 + -7 = -7 4c = -7 Divide each side by '4'. c = -1.75 Simplifying c = -1.75

Solution

c = {-3, -1.75}

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